c2=3.07

Solution for c2=3.07 equation:

c2=3.07

We move all terms to the left:

c2-(3.07)=0

We add all the numbers together, and all the variables

c^2-3.07=0

a = 1; b = 0; c = -3.07;
Δ = b2-4ac
Δ = 02-4·1·(-3.07)
Δ = 12.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.28}}{2*1}=\frac{0-\sqrt{12.28}}{2}
=-\frac{\sqrt{}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.28}}{2*1}=\frac{0+\sqrt{12.28}}{2}
=\frac{\sqrt{}}{2}
$