c=-13+(9-3c)

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Solution for c=-13+(9-3c) equation: 



c=-13+(9-3c)

We move all terms to the left:

c-(-13+(9-3c))=0

We add all the numbers together, and all the variables

c-(-13+(-3c+9))=0



We calculate terms in parentheses: -(-13+(-3c+9)), so:

-13+(-3c+9)

determiningTheFunctionDomain
(-3c+9)-13

We get rid of parentheses

-3c+9-13

We add all the numbers together, and all the variables

-3c-4

Back to the equation:

-(-3c-4)



We get rid of parentheses

c+3c+4=0

We add all the numbers together, and all the variables

4c+4=0

We move all terms containing c to the left, all other terms to the right

4c=-4

c=-4/4

c=-1

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