c=-28;-101/2c

Solution for c=-28;-101/2c equation:

c=-28-101/2c

We move all terms to the left:

c-(-28-101/2c)=0


Domain of the equation: 2c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

c-(-101/2c-28)=0

We get rid of parentheses

c+101/2c+28=0

We multiply all the terms by the denominator


c*2c+28*2c+101=0

Wy multiply elements

2c^2+56c+101=0

a = 2; b = 56; c = +101;
Δ = b2-4ac
Δ = 562-4·2·101
Δ = 2328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2328}=\sqrt{4*582}=\sqrt{4}*\sqrt{582}=2\sqrt{582}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-2\sqrt{582}}{2*2}=\frac{-56-2\sqrt{582}}{4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+2\sqrt{582}}{2*2}=\frac{-56+2\sqrt{582}}{4}
$