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c=1/4c-10
We move all terms to the left:
c-(1/4c-10)=0
Domain of the equation: 4c-10)!=0We get rid of parentheses
c∈R
c-1/4c+10=0
We multiply all the terms by the denominator
c*4c+10*4c-1=0
Wy multiply elements
4c^2+40c-1=0
a = 4; b = 40; c = -1;
Δ = b2-4ac
Δ = 402-4·4·(-1)
Δ = 1616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1616}=\sqrt{16*101}=\sqrt{16}*\sqrt{101}=4\sqrt{101}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{101}}{2*4}=\frac{-40-4\sqrt{101}}{8} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{101}}{2*4}=\frac{-40+4\sqrt{101}}{8} $
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