c=12+2(3)+34-35/2

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Solution for c=12+2(3)+34-35/2 equation: 



c=12+2(3)+34-35/2

We move all terms to the left:

c-(12+2(3)+34-35/2)=0

We add all the numbers together, and all the variables

c-(-35/2+69)=0

We get rid of parentheses

c-69+35/2=0

We multiply all the terms by the denominator


c*2+35-69*2=0

We add all the numbers together, and all the variables

c*2-103=0

Wy multiply elements

2c-103=0

We move all terms containing c to the left, all other terms to the right

2c=103

c=103/2

c=51+1/2

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