c=5/3(k-23)

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Solution for c=5/3(k-23) equation: 


x in (-oo:+oo)

c = (5/3)*(k-23) // - (5/3)*(k-23)

c-((5/3)*(k-23)) = 0

(-5/3)*(k-23)+c = 0

c-5/3*(k-23) = 0

c-5/3*(k-23) = 0

c-5/3*k+115/3 = 0

c-5/3*k+115/3 = 0

x belongs to the empty set

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