c=7/3(k-88)

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Solution for c=7/3(k-88) equation: 


x in (-oo:+oo)

c = (7/3)*(k-88) // - (7/3)*(k-88)

c-((7/3)*(k-88)) = 0

(-7/3)*(k-88)+c = 0

c-7/3*(k-88) = 0

c-7/3*(k-88) = 0

c-7/3*k+616/3 = 0

c-7/3*k+616/3 = 0

x belongs to the empty set

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