If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
c = (9/4)*(k-27) // - (9/4)*(k-27)
c-((9/4)*(k-27)) = 0
(-9/4)*(k-27)+c = 0
c-9/4*(k-27) = 0
c-9/4*(k-27) = 0
c-9/4*k+243/4 = 0
c-9/4*k+243/4 = 0
x belongs to the empty set
| 2/7d-2=3d-45/7 | | -11=6+x | | 7-3k=8+2k | | 5x(x-3)+4(x+4)=31-7x^2 | | 2m+4.6=5.2 | | 14x+12x-3=8x+15 | | (4x^2+14x+11)/(x+2) | | z+29=22 | | 4x/3+1/6(x+1)=3 | | 2/3x+12=6 | | -4(2x-16)=-4(x+13)-12 | | -9(5)+y=3 | | d/7=12+d | | x^2-14x-40=0 | | 4-(7-6x)=2x-2 | | 0.93=0.15+0.3 | | -9(4)+y=3 | | 9-2x=15+4x | | -7x+8x-16=10 | | 1/3c=3c-9 | | 2x+4=2(3x) | | 8-5k=37 | | n^2-6n+27=0 | | 15-z/3=21 | | 7p+3p-p=108 | | 2x^2-9x+150=0 | | 44x^2=144 | | 1p+7p+8=90+14 | | 1/3(10x-9)=4 | | -5(x-2(2x-3))+1=2x-3 | | 5k+4=2k+28 | | 25+k/3=36 |