cos(2x)-7cos(x)+4=0

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Solution for cos(2x)-7cos(x)+4=0 equation: 


Simplifying
cos(2x) + -7cos(x) + 4 = 0

Remove parenthesis around (2x)
cos * 2x + -7cos(x) + 4 = 0

Reorder the terms for easier multiplication:
2cos * x + -7cos(x) + 4 = 0

Multiply cos * x
2cosx + -7cos(x) + 4 = 0

Multiply cos * x
2cosx + -7cosx + 4 = 0

Reorder the terms:
4 + 2cosx + -7cosx = 0

Combine like terms: 2cosx + -7cosx = -5cosx
4 + -5cosx = 0

Solving
4 + -5cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -5cosx = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -5cosx = 0 + -4
-5cosx = 0 + -4

Combine like terms: 0 + -4 = -4
-5cosx = -4

Divide each side by '-5osx'.
c = 0.8o-1s-1x-1

Simplifying
c = 0.8o-1s-1x-1

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