cos(4x-pi/2)

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Solution for cos(4x-pi/2) equation: 


x in (-oo:+oo)

cos(4*x-(pi/2)) = 0

cos(4*x-(pi/2)) = 0  <=>  4*x-(pi/2) = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

4*x-t_1-(pi/2) = 0

4*x-t_1-(pi/2) = 0 // + -t_1-(pi/2)

4*x = -(-t_1-(pi/2)) // : 4

x = (-(-t_1-(pi/2)))/4

x = (t_1+pi/2)/4

x = (pi*k_1+pi/2+pi/2)/4 i k_1 należy do I

x = (pi*k_1+pi/2+pi/2)/4

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