cos(7x)+cos(5x)=2cos(6x)(0)

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Solution for cos(7x)+cos(5x)=2cos(6x)(0) equation:


Simplifying
cos(7x) + cos(5x) = 2cos(6x)(0)

Remove parenthesis around (7x)
cos * 7x + cos(5x) = 2cos(6x)(0)

Reorder the terms for easier multiplication:
7cos * x + cos(5x) = 2cos(6x)(0)

Multiply cos * x
7cosx + cos(5x) = 2cos(6x)(0)

Remove parenthesis around (5x)
7cosx + cos * 5x = 2cos(6x)(0)

Reorder the terms for easier multiplication:
7cosx + 5cos * x = 2cos(6x)(0)

Multiply cos * x
7cosx + 5cosx = 2cos(6x)(0)

Combine like terms: 7cosx + 5cosx = 12cosx
12cosx = 2cos(6x)(0)

Remove parenthesis around (6x)
12cosx = 2cos * 6x(0)

Reorder the terms for easier multiplication:
12cosx = 2 * 6 * 0cos * x

Multiply 2 * 6
12cosx = 12 * 0cos * x

Multiply 12 * 0
12cosx = 0cos * x

Anything times zero is zero.
12cosx = 0cos * x

Solving
12cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '12'.
cosx = 0

Simplifying
cosx = 0

The solution to this equation could not be determined.

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