cos(x)+cos(2x)+cos(3x)=1

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Solution for cos(x)+cos(2x)+cos(3x)=1 equation: 


Simplifying
cos(x) + cos(2x) + cos(3x) = 1

Multiply cos * x
cosx + cos(2x) + cos(3x) = 1

Remove parenthesis around (2x)
cosx + cos * 2x + cos(3x) = 1

Reorder the terms for easier multiplication:
cosx + 2cos * x + cos(3x) = 1

Multiply cos * x
cosx + 2cosx + cos(3x) = 1

Remove parenthesis around (3x)
cosx + 2cosx + cos * 3x = 1

Reorder the terms for easier multiplication:
cosx + 2cosx + 3cos * x = 1

Multiply cos * x
cosx + 2cosx + 3cosx = 1

Combine like terms: cosx + 2cosx = 3cosx
3cosx + 3cosx = 1

Combine like terms: 3cosx + 3cosx = 6cosx
6cosx = 1

Solving
6cosx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '6osx'.
c = 0.1666666667o-1s-1x-1

Simplifying
c = 0.1666666667o-1s-1x-1

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