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1/((1-x)^3)
log(10)(x^2-(2*x)-2) < 0
(e^-2)^x
-2*(3*a+1)*(a-2) = 0
5*x+3*y;-x-(2*y)-7
| 10+125x= | | 6x+60=8x-20 | | 8.78+1.6+8.53= | | y^2+3y-1.125=0 | | 4n-n=42 | | 6x+-2=4x+6 | | 6(x+4)-2(x-7)=10 | | 2(2.5b-7)+6b=-7 | | 6x-6+2x+18=36 | | [-5+(-10+4)]+(-7+5)= | | X+3+2x+2=-16 | | 6-7x=6x-8x+16 | | 9c-8-(c+6)= | | 10x-125= | | F(x)=-2t+2 | | 0.09xX=85.75 | | 3y-16=11 | | 58=6x+5x+3x | | F(4)=7x+3 | | -9+2x-4x=-31 | | AB=300 | | 45=2x+4x-3 | | 96=P(4)+16 | | x^2-3x=22.167 | | 6-.04h=11 | | -3x+9+7x=17 | | 0.29x*0.11=20 | | 11.6+(1.18*50)+(3.86*15.5)-(2.32*13.5)= | | 10x+26=64 | | 40*12x=25*15 | | 2=2y-16 | | 5x+8y+7=7x+11 |