d(d+4)=d2+4

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Solution for d(d+4)=d2+4 equation: 



d(d+4)=d2+4

We move all terms to the left:

d(d+4)-(d2+4)=0

We add all the numbers together, and all the variables

-(+d^2+4)+d(d+4)=0

We multiply parentheses

-(+d^2+4)+d^2+4d=0

We get rid of parentheses

-d^2+d^2+4d-4=0

We add all the numbers together, and all the variables

4d-4=0

We move all terms containing d to the left, all other terms to the right

4d=4

d=4/4

d=1

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