d+(2d+1)=4d+8+3/4+d=121

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Solution for d+(2d+1)=4d+8+3/4+d=121 equation: 



d+(2d+1)=4d+8+3/4+d=121

We move all terms to the left:

d+(2d+1)-(4d+8+3/4+d)=0



Domain of the equation: 4+d)!=0

We move all terms containing d to the left, all other terms to the right

d)!=-4

d!=-4/1

d!=-4

d∈R



We add all the numbers together, and all the variables

d+(2d+1)-(5d+3/4+8)=0

We get rid of parentheses

d+2d-5d+1-8-3/4=0

We multiply all the terms by the denominator


d*4+2d*4-5d*4-3+1*4-8*4=0

We add all the numbers together, and all the variables

d*4+2d*4-5d*4-31=0

Wy multiply elements

4d+8d-20d-31=0

We add all the numbers together, and all the variables

-8d-31=0

We move all terms containing d to the left, all other terms to the right

-8d=31

d=31/-8

d=-3+7/8

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