d+(d+3)+(d/2)+((d*2)*2)=17

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Solution for d+(d+3)+(d/2)+((d*2)*2)=17 equation: 



d+(d+3)+(d/2)+((d*2)*2)=17

We move all terms to the left:

d+(d+3)+(d/2)+((d*2)*2)-(17)=0

We add all the numbers together, and all the variables

d+(d+3)+(+d/2)+((+d*2)*2)-17=0

We get rid of parentheses

d+d+d/2+((+d*2)*2)+3-17=0

We multiply all the terms by the denominator


d*2+d*2+d+(((+d*2)*2))*2+3*2-17*2=0

We add all the numbers together, and all the variables

d+d*2+d*2+(((+d*2)*2))*2-28=0

Wy multiply elements

d+2d+2d+(((+d*2)*2))*2-28=0

We add all the numbers together, and all the variables

5d+(((+d*2)*2))*2-28=0

We move all terms containing d to the left, all other terms to the right

5d+(((+d*2)*2))*2=28

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