d+1/2d=3+7

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Solution for d+1/2d=3+7 equation:



d+1/2d=3+7
We move all terms to the left:
d+1/2d-(3+7)=0
Domain of the equation: 2d!=0
d!=0/2
d!=0
d∈R
We add all the numbers together, and all the variables
d+1/2d-10=0
We multiply all the terms by the denominator
d*2d-10*2d+1=0
Wy multiply elements
2d^2-20d+1=0
a = 2; b = -20; c = +1;
Δ = b2-4ac
Δ = -202-4·2·1
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-14\sqrt{2}}{2*2}=\frac{20-14\sqrt{2}}{4} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+14\sqrt{2}}{2*2}=\frac{20+14\sqrt{2}}{4} $

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