d+2(d+1)+3(d+2)=116

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Solution for d+2(d+1)+3(d+2)=116 equation:


Simplifying
d + 2(d + 1) + 3(d + 2) = 116

Reorder the terms:
d + 2(1 + d) + 3(d + 2) = 116
d + (1 * 2 + d * 2) + 3(d + 2) = 116
d + (2 + 2d) + 3(d + 2) = 116

Reorder the terms:
d + 2 + 2d + 3(2 + d) = 116
d + 2 + 2d + (2 * 3 + d * 3) = 116
d + 2 + 2d + (6 + 3d) = 116

Reorder the terms:
2 + 6 + d + 2d + 3d = 116

Combine like terms: 2 + 6 = 8
8 + d + 2d + 3d = 116

Combine like terms: d + 2d = 3d
8 + 3d + 3d = 116

Combine like terms: 3d + 3d = 6d
8 + 6d = 116

Solving
8 + 6d = 116

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 6d = 116 + -8

Combine like terms: 8 + -8 = 0
0 + 6d = 116 + -8
6d = 116 + -8

Combine like terms: 116 + -8 = 108
6d = 108

Divide each side by '6'.
d = 18

Simplifying
d = 18

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