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d+3/4d=336
We move all terms to the left:
d+3/4d-(336)=0
Domain of the equation: 4d!=0We multiply all the terms by the denominator
d!=0/4
d!=0
d∈R
d*4d-336*4d+3=0
Wy multiply elements
4d^2-1344d+3=0
a = 4; b = -1344; c = +3;
Δ = b2-4ac
Δ = -13442-4·4·3
Δ = 1806288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1806288}=\sqrt{1936*933}=\sqrt{1936}*\sqrt{933}=44\sqrt{933}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1344)-44\sqrt{933}}{2*4}=\frac{1344-44\sqrt{933}}{8} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1344)+44\sqrt{933}}{2*4}=\frac{1344+44\sqrt{933}}{8} $
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