d+3=-10-7/3d

Solution for d+3=-10-7/3d equation:

d+3=-10-7/3d

We move all terms to the left:

d+3-(-10-7/3d)=0


Domain of the equation: 3d)!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

d-(-7/3d-10)+3=0

We get rid of parentheses

d+7/3d+10+3=0

We multiply all the terms by the denominator


d*3d+10*3d+3*3d+7=0

Wy multiply elements

3d^2+30d+9d+7=0

We add all the numbers together, and all the variables

3d^2+39d+7=0

a = 3; b = 39; c = +7;
Δ = b2-4ac
Δ = 392-4·3·7
Δ = 1437
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{1437}}{2*3}=\frac{-39-\sqrt{1437}}{6}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{1437}}{2*3}=\frac{-39+\sqrt{1437}}{6}
$