d+4(d+3)+2(d+5)=57

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Solution for d+4(d+3)+2(d+5)=57 equation:


Simplifying
d + 4(d + 3) + 2(d + 5) = 57

Reorder the terms:
d + 4(3 + d) + 2(d + 5) = 57
d + (3 * 4 + d * 4) + 2(d + 5) = 57
d + (12 + 4d) + 2(d + 5) = 57

Reorder the terms:
d + 12 + 4d + 2(5 + d) = 57
d + 12 + 4d + (5 * 2 + d * 2) = 57
d + 12 + 4d + (10 + 2d) = 57

Reorder the terms:
12 + 10 + d + 4d + 2d = 57

Combine like terms: 12 + 10 = 22
22 + d + 4d + 2d = 57

Combine like terms: d + 4d = 5d
22 + 5d + 2d = 57

Combine like terms: 5d + 2d = 7d
22 + 7d = 57

Solving
22 + 7d = 57

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 7d = 57 + -22

Combine like terms: 22 + -22 = 0
0 + 7d = 57 + -22
7d = 57 + -22

Combine like terms: 57 + -22 = 35
7d = 35

Divide each side by '7'.
d = 5

Simplifying
d = 5

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