d-4/5d+10=15

Solution for d-4/5d+10=15 equation:

d-4/5d+10=15

We move all terms to the left:

d-4/5d+10-(15)=0


Domain of the equation: 5d!=0

d!=0/5

d!=0

d∈R


We add all the numbers together, and all the variables

d-4/5d-5=0

We multiply all the terms by the denominator


d*5d-5*5d-4=0

Wy multiply elements

5d^2-25d-4=0

a = 5; b = -25; c = -4;
Δ = b2-4ac
Δ = -252-4·5·(-4)
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{705}}{2*5}=\frac{25-\sqrt{705}}{10}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{705}}{2*5}=\frac{25+\sqrt{705}}{10}
$