Derivative of (0.5)ln(100-x)

Derivative of (0.5)ln(100-x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of (0.5)ln(100-x): 


(0.5*ln(100-x))'

(0.5)'*ln(100-x)+0.5*(ln(100-x))'

0*ln(100-x)+0.5*(ln(100-x))'

0*ln(100-x)+0.5*(1/(100-x))*(100-x)'

0*ln(100-x)+0.5*(1/(100-x))*((-x)'+(100)')

0*ln(100-x)+0.5*((100)'-1)*(1/(100-x))

0*ln(100-x)+0.5*(0-1)*(1/(100-x))

0*ln(100-x)+0.5*(-(100-x)^-1)

0.5*(-(100-x)^-1)

The calculation above is a derivative of the function f (x)

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