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(1/(x-3))'The calculation above is a derivative of the function f (x)
((1)'*(x-3)-(1*(x-3)'))/((x-3)^2)
(0*(x-3)-(1*(x-3)'))/((x-3)^2)
(0*(x-3)-(1*((x)'+(-3)')))/((x-3)^2)
(0*(x-3)-(1*((-3)'+1)))/((x-3)^2)
(0*(x-3)-(1*(0+1)))/((x-3)^2)
(0*(x-3)-(1*1))/((x-3)^2)
-1/((x-3)^2)
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