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((2*x+2)^3000)'The calculation above is a derivative of the function f (x)
3000*(2*x+2)^(3000-1)*(2*x+2)'
3000*(2*x+2)^(3000-1)*((2*x)'+(2)')
3000*(2*x+2)^(3000-1)*(2*(x)'+(2)'*x+(2)')
3000*(2*x+2)^(3000-1)*(2*(x)'+0*x+(2)')
3000*(2*x+2)^(3000-1)*(0*x+2*1+(2)')
3000*(2*x+2)^(3000-1)*(0+2)
3000*(2*x+2)^(3000-1)*2
6000*(2*x+2)^2999
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