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((30-x)/10)'The calculation above is a derivative of the function f (x)
((30-x)'*10-((30-x)*(10)'))/(10^2)
(((-x)'+(30)')*10-((30-x)*(10)'))/(10^2)
(((30)'-1)*10-((30-x)*(10)'))/(10^2)
((0-1)*10-((30-x)*(10)'))/(10^2)
(-1*10-((30-x)*(10)'))/(10^2)
(-1*10-((30-x)*0))/(10^2)
-1/10
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