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(sin(2*x)/cos(x))'The calculation above is a derivative of the function f (x)
((sin(2*x))'*cos(x)-(sin(2*x)*(cos(x))'))/((cos(x))^2)
(cos(2*x)*(2*x)'*cos(x)-(sin(2*x)*(cos(x))'))/((cos(x))^2)
(cos(2*x)*((2)'*x+2*(x)')*cos(x)-(sin(2*x)*(cos(x))'))/((cos(x))^2)
(cos(2*x)*(0*x+2*(x)')*cos(x)-(sin(2*x)*(cos(x))'))/((cos(x))^2)
(cos(2*x)*(0*x+2*1)*cos(x)-(sin(2*x)*(cos(x))'))/((cos(x))^2)
(2*cos(2*x)*cos(x)-(sin(2*x)*(cos(x))'))/((cos(x))^2)
(2*cos(2*x)*cos(x)-(sin(2*x)*(-sin(x))))/((cos(x))^2)
(2*cos(2*x)*cos(x)+sin(x)*sin(2*x))/((cos(x))^2)
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