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(1/(x+1))'The calculation above is a derivative of the function f (x)
((1)'*(x+1)-(1*(x+1)'))/((x+1)^2)
(0*(x+1)-(1*(x+1)'))/((x+1)^2)
(0*(x+1)-(1*((x)'+(1)')))/((x+1)^2)
(0*(x+1)-(1*((1)'+1)))/((x+1)^2)
(0*(x+1)-(1*(0+1)))/((x+1)^2)
(0*(x+1)-(1*1))/((x+1)^2)
-1/((x+1)^2)
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