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(1/(x+y))'The calculation above is a derivative of the function f (x)
((1)'*(x+y)-(1*(x+y)'))/((x+y)^2)
(0*(x+y)-(1*(x+y)'))/((x+y)^2)
(0*(x+y)-(1*((x)'+(y)')))/((x+y)^2)
(0*(x+y)-(1*((y)'+1)))/((x+y)^2)
(0*(x+y)-(1*(0+1)))/((x+y)^2)
(0*(x+y)-(1*1))/((x+y)^2)
-1/((x+y)^2)
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