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((1/2)*ln(-10*x))'The calculation above is a derivative of the function f (x)
(1/2)'*ln(-10*x)+(1/2)*(ln(-10*x))'
0*ln(-10*x)+(1/2)*(ln(-10*x))'
0*ln(-10*x)+(1/2)*(1/(-10*x))*(-10*x)'
0*ln(-10*x)+(1/2)*(1/(-10*x))*((-10)'*x-10*(x)')
0*ln(-10*x)+(1/2)*(1/(-10*x))*(0*x-10*(x)')
0*ln(-10*x)+(1/2)*(1/(-10*x))*(0*x-10*1)
0*ln(-10*x)+(1/2)*x^-1
(1/2)*x^-1
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