Derivative of 1/sin(2x)

Derivative of 1/sin(2x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 1/sin(2x): 


(1/sin(2*x))'

((1)'*sin(2*x)-(1*(sin(2*x))'))/((sin(2*x))^2)

(0*sin(2*x)-(1*(sin(2*x))'))/((sin(2*x))^2)

(0*sin(2*x)-(1*cos(2*x)*(2*x)'))/((sin(2*x))^2)

(0*sin(2*x)-(1*cos(2*x)*((2)'*x+2*(x)')))/((sin(2*x))^2)

(0*sin(2*x)-(1*cos(2*x)*(0*x+2*(x)')))/((sin(2*x))^2)

(0*sin(2*x)-(1*cos(2*x)*(0*x+2*1)))/((sin(2*x))^2)

(0*sin(2*x)-(1*2*cos(2*x)))/((sin(2*x))^2)

(-2*cos(2*x))/((sin(2*x))^2)

The calculation above is a derivative of the function f (x)

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