Derivative of 2*cos(2*x)*cos(x)-(sin(x)*sin(2*x))

Derivative of 2*cos(2*x)*cos(x)-(sin(x)*sin(2*x)). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 2*cos(2*x)*cos(x)-(sin(x)*sin(2*x)): 


(2*cos(2*x)*cos(x)-(sin(x)*sin(2*x)))'

(2*cos(2*x)*cos(x))'+(-(sin(x)*sin(2*x)))'

(2*cos(2*x))'*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

((2)'*cos(2*x)+2*(cos(2*x))')*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*(cos(2*x))')*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*-sin(2*x)*(2*x)')*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*-sin(2*x)*((2)'*x+2*(x)'))*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*-sin(2*x)*(0*x+2*(x)'))*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*-sin(2*x)*(0*x+2*1))*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*2*(-sin(2*x)))*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

(0*cos(2*x)+2*-2*sin(2*x))*cos(x)+2*cos(2*x)*(cos(x))'+(-(sin(x)*sin(2*x)))'

2*cos(2*x)*(cos(x))'-4*sin(2*x)*cos(x)+(-(sin(x)*sin(2*x)))'

2*cos(2*x)*(-sin(x))-4*sin(2*x)*cos(x)+(-(sin(x)*sin(2*x)))'

(sin(x))'*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*(sin(2*x))'

cos(x)*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*(sin(2*x))'

cos(x)*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*cos(2*x)*(2*x)'

cos(x)*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*cos(2*x)*((2)'*x+2*(x)')

cos(x)*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*cos(2*x)*(0*x+2*(x)')

cos(x)*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*cos(2*x)*(0*x+2*1)

cos(x)*sin(2*x)-4*sin(2*x)*cos(x)-2*sin(x)*cos(2*x)+sin(x)*2*cos(2*x)

-4*sin(x)*cos(2*x)-(4*sin(2*x)*cos(x))-(cos(x)*sin(2*x))

The calculation above is a derivative of the function f (x)

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