Derivative of 2cos(x)/-2sin(x)

Derivative of 2cos(x)/-2sin(x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 2cos(x)/-2sin(x): 


(((2*cos(x))/(-2))*sin(x))'

((2*cos(x))/(-2))'*sin(x)+((2*cos(x))/(-2))*(sin(x))'

(((2*cos(x))'*(-2)-(2*cos(x)*(-2)'))/((-2)^2))*sin(x)+((2*cos(x))/(-2))*(sin(x))'

((((2)'*cos(x)+2*(cos(x))')*(-2)-(2*cos(x)*(-2)'))/((-2)^2))*sin(x)+((2*cos(x))/(-2))*(sin(x))'

(((0*cos(x)+2*(cos(x))')*(-2)-(2*cos(x)*(-2)'))/((-2)^2))*sin(x)+((2*cos(x))/(-2))*(sin(x))'

(((0*cos(x)+2*(-sin(x)))*(-2)-(2*cos(x)*(-2)'))/((-2)^2))*sin(x)+((2*cos(x))/(-2))*(sin(x))'

((-2*sin(x)*(-2)-(2*cos(x)*(-2)'))/((-2)^2))*sin(x)+((2*cos(x))/(-2))*(sin(x))'

((-2*sin(x)*(-2)-(2*cos(x)*0))/((-2)^2))*sin(x)+((2*cos(x))/(-2))*(sin(x))'

sin(x)*sin(x)+((2*cos(x))/(-2))*(sin(x))'

sin(x)*sin(x)+((2*cos(x))/(-2))*cos(x)

(sin(x))^2-(cos(x))^2

The calculation above is a derivative of the function f (x)

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