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(3*ln(x+3))'The calculation above is a derivative of the function f (x)
(3)'*ln(x+3)+3*(ln(x+3))'
0*ln(x+3)+3*(ln(x+3))'
0*ln(x+3)+3*(1/(x+3))*(x+3)'
0*ln(x+3)+3*(1/(x+3))*((x)'+(3)')
0*ln(x+3)+3*((3)'+1)*(1/(x+3))
0*ln(x+3)+3*(0+1)*(1/(x+3))
0*ln(x+3)+3*(1/(x+3))
3/(x+3)
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