Derivative of 5sin(3x)cos(2x)

Derivative of 5sin(3x)cos(2x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 5sin(3x)cos(2x): 


(5*sin(3*x)*cos(2*x))'

(5*sin(3*x))'*cos(2*x)+5*sin(3*x)*(cos(2*x))'

((5)'*sin(3*x)+5*(sin(3*x))')*cos(2*x)+5*sin(3*x)*(cos(2*x))'

(0*sin(3*x)+5*(sin(3*x))')*cos(2*x)+5*sin(3*x)*(cos(2*x))'

(0*sin(3*x)+5*cos(3*x)*(3*x)')*cos(2*x)+5*sin(3*x)*(cos(2*x))'

(0*sin(3*x)+5*cos(3*x)*((3)'*x+3*(x)'))*cos(2*x)+5*sin(3*x)*(cos(2*x))'

(0*sin(3*x)+5*cos(3*x)*(0*x+3*(x)'))*cos(2*x)+5*sin(3*x)*(cos(2*x))'

(0*sin(3*x)+5*cos(3*x)*(0*x+3*1))*cos(2*x)+5*sin(3*x)*(cos(2*x))'

(0*sin(3*x)+5*3*cos(3*x))*cos(2*x)+5*sin(3*x)*(cos(2*x))'

15*cos(3*x)*cos(2*x)+5*sin(3*x)*(cos(2*x))'

15*cos(3*x)*cos(2*x)+5*sin(3*x)*-sin(2*x)*(2*x)'

15*cos(3*x)*cos(2*x)+5*sin(3*x)*-sin(2*x)*((2)'*x+2*(x)')

15*cos(3*x)*cos(2*x)+5*sin(3*x)*-sin(2*x)*(0*x+2*(x)')

15*cos(3*x)*cos(2*x)+5*sin(3*x)*-sin(2*x)*(0*x+2*1)

15*cos(3*x)*cos(2*x)+5*sin(3*x)*2*(-sin(2*x))

15*cos(3*x)*cos(2*x)+5*sin(3*x)*-2*sin(2*x)

15*cos(3*x)*cos(2*x)-(10*sin(3*x)*sin(2*x))

The calculation above is a derivative of the function f (x)

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