Derivative of sin(Pi*x)/cos(-Pi*x)

Derivative of sin(Pi*x)/cos(-Pi*x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of sin(Pi*x)/cos(-Pi*x): 


(sin(pi*x)/cos(-pi*x))'

((sin(pi*x))'*cos(-pi*x)-(sin(pi*x)*(cos(-pi*x))'))/((cos(-pi*x))^2)

(cos(pi*x)*(pi*x)'*cos(-pi*x)-(sin(pi*x)*(cos(-pi*x))'))/((cos(-pi*x))^2)

(cos(pi*x)*((pi)'*x+pi*(x)')*cos(-pi*x)-(sin(pi*x)*(cos(-pi*x))'))/((cos(-pi*x))^2)

(cos(pi*x)*(0*x+pi*(x)')*cos(-pi*x)-(sin(pi*x)*(cos(-pi*x))'))/((cos(-pi*x))^2)

(cos(pi*x)*(0*x+pi*1)*cos(-pi*x)-(sin(pi*x)*(cos(-pi*x))'))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*(cos(-pi*x))'))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*-sin(-pi*x)*(-pi*x)'))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*-sin(-pi*x)*((-pi)'*x-pi*(x)')))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*-sin(-pi*x)*(0*x-pi*(x)')))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*-sin(-pi*x)*(0*x-pi*1)))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*-pi*(-sin(-pi*x))))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-pi*x)-(sin(pi*x)*pi*sin(-(pi*x))))/((cos(-pi*x))^2)

(pi*cos(pi*x)*cos(-(pi*x))-(pi*sin(pi*x)*sin(-(pi*x))))/((cos(-(pi*x)))^2)

The calculation above is a derivative of the function f (x)

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