dy/dx=(tany)(cotx)-(secy)(cosx)

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Solution for dy/dx=(tany)(cotx)-(secy)(cosx) equation: 


ln(11*x)/ln(6*x) = 0

110/40 = 0

(1/2)*m = 9/10

(14*a)/3 = 7/9

(7/10)*x = 70

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