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e-6=1/3e
We move all terms to the left:
e-6-(1/3e)=0
Domain of the equation: 3e)!=0We add all the numbers together, and all the variables
e!=0/1
e!=0
e∈R
e-(+1/3e)-6=0
We get rid of parentheses
e-1/3e-6=0
We multiply all the terms by the denominator
e*3e-6*3e-1=0
Wy multiply elements
3e^2-18e-1=0
a = 3; b = -18; c = -1;
Δ = b2-4ac
Δ = -182-4·3·(-1)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-4\sqrt{21}}{2*3}=\frac{18-4\sqrt{21}}{6} $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+4\sqrt{21}}{2*3}=\frac{18+4\sqrt{21}}{6} $
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