f(0)=16,f(2)=8

Solution for f(0)=16,f(2)=8 equation:

f(0)=16.f(2)=8

We move all terms to the left:

f(0)-(16.f(2))=0

We add all the numbers together, and all the variables

-(+16.f^2)+f0=0

We add all the numbers together, and all the variables

-(+16.f^2)+f=0

We get rid of parentheses

-16.f^2+f=0

We add all the numbers together, and all the variables

-16f^2+f=0

a = -16; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-16)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-16}=\frac{-2}{-32}
=1/16
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-16}=\frac{0}{-32}
=0
$