f(0)=3sin(2x)+4cos(3x)

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Solution for f(0)=3sin(2x)+4cos(3x) equation:


Simplifying
f(0) = 3sin(2x) + 4cos(3x)

Reorder the terms for easier multiplication:
0f = 3sin(2x) + 4cos(3x)

Anything times zero is zero.
0f = 3sin(2x) + 4cos(3x)

Remove parenthesis around (2x)
0 = 3ins * 2x + 4cos(3x)

Reorder the terms for easier multiplication:
0 = 3 * 2ins * x + 4cos(3x)

Multiply 3 * 2
0 = 6ins * x + 4cos(3x)

Multiply ins * x
0 = 6insx + 4cos(3x)

Remove parenthesis around (3x)
0 = 6insx + 4cos * 3x

Reorder the terms for easier multiplication:
0 = 6insx + 4 * 3cos * x

Multiply 4 * 3
0 = 6insx + 12cos * x

Multiply cos * x
0 = 6insx + 12cosx

Reorder the terms:
0 = 12cosx + 6insx

Solving
0 = 12cosx + 6insx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-12cosx' to each side of the equation.
0 + -12cosx = 12cosx + -12cosx + 6insx
Remove the zero:
-12cosx = 12cosx + -12cosx + 6insx

Combine like terms: 12cosx + -12cosx = 0
-12cosx = 0 + 6insx
-12cosx = 6insx

Divide each side by '-12osx'.
c = -0.5ino-1

Simplifying
c = -0.5ino-1

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