f(2)=-3(2)+12

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Solution for f(2)=-3(2)+12 equation: 



f(2)=-3(2)+12

We move all terms to the left:

f(2)-(-3(2)+12)=0

We add all the numbers together, and all the variables

f2-(-20)=0

We add all the numbers together, and all the variables

f^2+20=0

a = 1; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·1·20
Δ = -80
Delta is less than zero, so there is no solution for the equation

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