f(2)=12(0.82)

Solution for f(2)=12(0.82) equation:

f(2)=12(0.82)

We move all terms to the left:

f(2)-(12(0.82))=0

We add all the numbers together, and all the variables

f^2-9.84=0

a = 1; b = 0; c = -9.84;
Δ = b2-4ac
Δ = 02-4·1·(-9.84)
Δ = 39.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{39.36}}{2*1}=\frac{0-\sqrt{39.36}}{2}
=-\frac{\sqrt{}}{2}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{39.36}}{2*1}=\frac{0+\sqrt{39.36}}{2}
=\frac{\sqrt{}}{2}
$