f(2+1)=f(2)+6(2+1)+1

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Solution for f(2+1)=f(2)+6(2+1)+1 equation: 



f(2+1)=f(2)+6(2+1)+1

We move all terms to the left:

f(2+1)-(f(2)+6(2+1)+1)=0

We add all the numbers together, and all the variables

f3-(f2+63+1)=0

We add all the numbers together, and all the variables

f^3-(f2+63+1)=0

We get rid of parentheses

f^3-f2-63-1=0

We do not support efpression: f^3

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