f(2m-5)=3(2m-5)+7

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Solution for f(2m-5)=3(2m-5)+7 equation:


Simplifying
f(2m + -5) = 3(2m + -5) + 7

Reorder the terms:
f(-5 + 2m) = 3(2m + -5) + 7
(-5 * f + 2m * f) = 3(2m + -5) + 7
(-5f + 2fm) = 3(2m + -5) + 7

Reorder the terms:
-5f + 2fm = 3(-5 + 2m) + 7
-5f + 2fm = (-5 * 3 + 2m * 3) + 7
-5f + 2fm = (-15 + 6m) + 7

Reorder the terms:
-5f + 2fm = -15 + 7 + 6m

Combine like terms: -15 + 7 = -8
-5f + 2fm = -8 + 6m

Solving
-5f + 2fm = -8 + 6m

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
8 + -5f + 2fm + -6m = -8 + 6m + 8 + -6m

Reorder the terms:
8 + -5f + 2fm + -6m = -8 + 8 + 6m + -6m

Combine like terms: -8 + 8 = 0
8 + -5f + 2fm + -6m = 0 + 6m + -6m
8 + -5f + 2fm + -6m = 6m + -6m

Combine like terms: 6m + -6m = 0
8 + -5f + 2fm + -6m = 0

The solution to this equation could not be determined.

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