f(5+2)=f(5+1)+4f(5)

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Solution for f(5+2)=f(5+1)+4f(5) equation: 



f(5+2)=f(5+1)+4f(5)

We move all terms to the left:

f(5+2)-(f(5+1)+4f(5))=0

We add all the numbers together, and all the variables

f7-(f6+4f5)=0

We add all the numbers together, and all the variables

f^7-(f6+4f5)=0

We get rid of parentheses

f^7-f6-4f5=0

We do not support efpression: f^7

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