f(X)=20X+49-10(X+8)

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Solution for f(X)=20X+49-10(X+8) equation: 



f(f)=20f+49-10(f+8)

We move all terms to the left:

f(f)-(20f+49-10(f+8))=0



We calculate terms in parentheses: -(20f+49-10(f+8)), so:

20f+49-10(f+8)

determiningTheFunctionDomain
20f-10(f+8)+49

We multiply parentheses

20f-10f-80+49

We add all the numbers together, and all the variables

10f-31

Back to the equation:

-(10f-31)



We get rid of parentheses

ff-10f+31=0

We add all the numbers together, and all the variables

-10f+ff+31=0

We move all terms containing f to the left, all other terms to the right

-10f+ff=-31

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