f(k+2)=3(k+2)+7

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Solution for f(k+2)=3(k+2)+7 equation: 


Simplifying
f(k + 2) = 3(k + 2) + 7

Reorder the terms:
f(2 + k) = 3(k + 2) + 7
(2 * f + k * f) = 3(k + 2) + 7
(2f + fk) = 3(k + 2) + 7

Reorder the terms:
2f + fk = 3(2 + k) + 7
2f + fk = (2 * 3 + k * 3) + 7
2f + fk = (6 + 3k) + 7

Reorder the terms:
2f + fk = 6 + 7 + 3k

Combine like terms: 6 + 7 = 13
2f + fk = 13 + 3k

Solving
2f + fk = 13 + 3k

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-13 + 2f + fk + -3k = 13 + 3k + -13 + -3k

Reorder the terms:
-13 + 2f + fk + -3k = 13 + -13 + 3k + -3k

Combine like terms: 13 + -13 = 0
-13 + 2f + fk + -3k = 0 + 3k + -3k
-13 + 2f + fk + -3k = 3k + -3k

Combine like terms: 3k + -3k = 0
-13 + 2f + fk + -3k = 0

The solution to this equation could not be determined.

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