f(n)=(n-4)*(21)*(30n-5)

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Solution for f(n)=(n-4)*(21)*(30n-5) equation: 


Simplifying
f(n) = (n + -4)(21)(30n + -5)

Multiply f * n
fn = (n + -4)(21)(30n + -5)

Reorder the terms:
fn = (-4 + n)(21)(30n + -5)

Reorder the terms:
fn = (-4 + n) * 21(-5 + 30n)

Reorder the terms for easier multiplication:
fn = 21(-4 + n)(-5 + 30n)

Multiply (-4 + n) * (-5 + 30n)
fn = 21(-4(-5 + 30n) + n(-5 + 30n))
fn = 21((-5 * -4 + 30n * -4) + n(-5 + 30n))
fn = 21((20 + -120n) + n(-5 + 30n))
fn = 21(20 + -120n + (-5 * n + 30n * n))
fn = 21(20 + -120n + (-5n + 30n2))

Combine like terms: -120n + -5n = -125n
fn = 21(20 + -125n + 30n2)
fn = (20 * 21 + -125n * 21 + 30n2 * 21)
fn = (420 + -2625n + 630n2)

Solving
fn = 420 + -2625n + 630n2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'n'.
f = 420n-1 + -2625 + 630n

Simplifying
f = 420n-1 + -2625 + 630n

Reorder the terms:
f = -2625 + 420n-1 + 630n

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