f(n)=2f(n-1)+2

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Solution for f(n)=2f(n-1)+2 equation:


Simplifying
f(n) = 2f(n + -1) + 2

Multiply f * n
fn = 2f(n + -1) + 2

Reorder the terms:
fn = 2f(-1 + n) + 2
fn = (-1 * 2f + n * 2f) + 2
fn = (-2f + 2fn) + 2

Reorder the terms:
fn = 2 + -2f + 2fn

Solving
fn = 2 + -2f + 2fn

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
2f + fn = 2 + -2f + 2f + 2fn

Combine like terms: -2f + 2f = 0
2f + fn = 2 + 0 + 2fn
2f + fn = 2 + 2fn

Add '-2fn' to each side of the equation.
2f + fn + -2fn = 2 + 2fn + -2fn

Combine like terms: fn + -2fn = -1fn
2f + -1fn = 2 + 2fn + -2fn

Combine like terms: 2fn + -2fn = 0
2f + -1fn = 2 + 0
2f + -1fn = 2

Reorder the terms:
-2 + 2f + -1fn = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 2f + -1fn = 0

The solution to this equation could not be determined.

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