f(n)=2x(n-1)+f(n-2)

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Solution for f(n)=2x(n-1)+f(n-2) equation:


Simplifying
f(n) = 2x(n + -1) + f(n + -2)

Multiply f * n
fn = 2x(n + -1) + f(n + -2)

Reorder the terms:
fn = 2x(-1 + n) + f(n + -2)
fn = (-1 * 2x + n * 2x) + f(n + -2)

Reorder the terms:
fn = (2nx + -2x) + f(n + -2)
fn = (2nx + -2x) + f(n + -2)

Reorder the terms:
fn = 2nx + -2x + f(-2 + n)
fn = 2nx + -2x + (-2 * f + n * f)
fn = 2nx + -2x + (-2f + fn)

Reorder the terms:
fn = -2f + fn + 2nx + -2x

Add '-1fn' to each side of the equation.
fn + -1fn = -2f + fn + 2nx + -1fn + -2x

Combine like terms: fn + -1fn = 0
0 = -2f + fn + 2nx + -1fn + -2x

Reorder the terms:
0 = -2f + fn + -1fn + 2nx + -2x

Combine like terms: fn + -1fn = 0
0 = -2f + 0 + 2nx + -2x
0 = -2f + 2nx + -2x

Solving
0 = -2f + 2nx + -2x

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
0 + 2f = -2f + 2nx + 2f + -2x
Remove the zero:
2f = -2f + 2nx + 2f + -2x

Reorder the terms:
2f = -2f + 2f + 2nx + -2x

Combine like terms: -2f + 2f = 0
2f = 0 + 2nx + -2x
2f = 2nx + -2x

Divide each side by '2'.
f = nx + -1x

Simplifying
f = nx + -1x

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